(3b-4)4=2(b-5)

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Solution for (3b-4)4=2(b-5) equation: 



(3b-4)4=2(b-5)

We move all terms to the left:

(3b-4)4-(2(b-5))=0

We multiply parentheses

12b-(2(b-5))-16=0



We calculate terms in parentheses: -(2(b-5)), so:

2(b-5)

We multiply parentheses

2b-10

Back to the equation:

-(2b-10)



We get rid of parentheses

12b-2b+10-16=0

We add all the numbers together, and all the variables

10b-6=0

We move all terms containing b to the left, all other terms to the right

10b=6

b=6/10

b=3/5

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