(3b-4)8=4(b-1)

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Solution for (3b-4)8=4(b-1) equation: 



(3b-4)8=4(b-1)

We move all terms to the left:

(3b-4)8-(4(b-1))=0

We multiply parentheses

24b-(4(b-1))-32=0



We calculate terms in parentheses: -(4(b-1)), so:

4(b-1)

We multiply parentheses

4b-4

Back to the equation:

-(4b-4)



We get rid of parentheses

24b-4b+4-32=0

We add all the numbers together, and all the variables

20b-28=0

We move all terms containing b to the left, all other terms to the right

20b=28

b=28/20

b=1+2/5

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