(3b-4)=5(b+6)

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Solution for (3b-4)=5(b+6) equation: 



(3b-4)=5(b+6)

We move all terms to the left:

(3b-4)-(5(b+6))=0

We get rid of parentheses

3b-(5(b+6))-4=0



We calculate terms in parentheses: -(5(b+6)), so:

5(b+6)

We multiply parentheses

5b+30

Back to the equation:

-(5b+30)



We get rid of parentheses

3b-5b-30-4=0

We add all the numbers together, and all the variables

-2b-34=0

We move all terms containing b to the left, all other terms to the right

-2b=34

b=34/-2

b=-17

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