(3b-6)+(b-2)=90

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Solution for (3b-6)+(b-2)=90 equation: 



(3b-6)+(b-2)=90

We move all terms to the left:

(3b-6)+(b-2)-(90)=0

We get rid of parentheses

3b+b-6-2-90=0

We add all the numbers together, and all the variables

4b-98=0

We move all terms containing b to the left, all other terms to the right

4b=98

b=98/4

b=24+1/2

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