(3b-6)=(b-2)

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Solution for (3b-6)=(b-2) equation: 



(3b-6)=(b-2)

We move all terms to the left:

(3b-6)-((b-2))=0

We get rid of parentheses

3b-((b-2))-6=0



We calculate terms in parentheses: -((b-2)), so:

(b-2)

We get rid of parentheses

b-2

Back to the equation:

-(b-2)



We get rid of parentheses

3b-b+2-6=0

We add all the numbers together, and all the variables

2b-4=0

We move all terms containing b to the left, all other terms to the right

2b=4

b=4/2

b=2

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