(3b-9)+12=3b+3

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Solution for (3b-9)+12=3b+3 equation:


Simplifying
(3b + -9) + 12 = 3b + 3

Reorder the terms:
(-9 + 3b) + 12 = 3b + 3

Remove parenthesis around (-9 + 3b)
-9 + 3b + 12 = 3b + 3

Reorder the terms:
-9 + 12 + 3b = 3b + 3

Combine like terms: -9 + 12 = 3
3 + 3b = 3b + 3

Reorder the terms:
3 + 3b = 3 + 3b

Add '-3' to each side of the equation.
3 + -3 + 3b = 3 + -3 + 3b

Combine like terms: 3 + -3 = 0
0 + 3b = 3 + -3 + 3b
3b = 3 + -3 + 3b

Combine like terms: 3 + -3 = 0
3b = 0 + 3b
3b = 3b

Add '-3b' to each side of the equation.
3b + -3b = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 3b + -3b

Combine like terms: 3b + -3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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