(3b/6)+2b=10

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Solution for (3b/6)+2b=10 equation:



(3b/6)+2b=10
We move all terms to the left:
(3b/6)+2b-(10)=0
We add all the numbers together, and all the variables
(+3b/6)+2b-10=0
We add all the numbers together, and all the variables
2b+(+3b/6)-10=0
We get rid of parentheses
2b+3b/6-10=0
We multiply all the terms by the denominator
2b*6+3b-10*6=0
We add all the numbers together, and all the variables
3b+2b*6-60=0
Wy multiply elements
3b+12b-60=0
We add all the numbers together, and all the variables
15b-60=0
We move all terms containing b to the left, all other terms to the right
15b=60
b=60/15
b=4

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