(3c+1)2=11

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Solution for (3c+1)2=11 equation: 



(3c+1)2=11

We move all terms to the left:

(3c+1)2-(11)=0

We multiply parentheses

6c+2-11=0

We add all the numbers together, and all the variables

6c-9=0

We move all terms containing c to the left, all other terms to the right

6c=9

c=9/6

c=1+1/2

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