(3c+1)=(c-2)

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Solution for (3c+1)=(c-2) equation: 



(3c+1)=(c-2)

We move all terms to the left:

(3c+1)-((c-2))=0

We get rid of parentheses

3c-((c-2))+1=0



We calculate terms in parentheses: -((c-2)), so:

(c-2)

We get rid of parentheses

c-2

Back to the equation:

-(c-2)



We get rid of parentheses

3c-c+2+1=0

We add all the numbers together, and all the variables

2c+3=0

We move all terms containing c to the left, all other terms to the right

2c=-3

c=-3/2

c=-1+1/2

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