(3c+2)(3c-2)=

Solution for (3c+2)(3c-2)= equation:

Simplifying
(3c + 2)(3c + -2) = 0

Reorder the terms:
(2 + 3c)(3c + -2) = 0

Reorder the terms:
(2 + 3c)(-2 + 3c) = 0

Multiply (2 + 3c) * (-2 + 3c)
(2(-2 + 3c) + 3c * (-2 + 3c)) = 0
((-2 * 2 + 3c * 2) + 3c * (-2 + 3c)) = 0
((-4 + 6c) + 3c * (-2 + 3c)) = 0
(-4 + 6c + (-2 * 3c + 3c * 3c)) = 0
(-4 + 6c + (-6c + 9c2)) = 0

Combine like terms: 6c + -6c = 0
(-4 + 0 + 9c2) = 0
(-4 + 9c2) = 0

Solving
-4 + 9c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 9c2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 9c2 = 0 + 4
9c2 = 0 + 4

Combine like terms: 0 + 4 = 4
9c2 = 4

Divide each side by '9'.
c2 = 0.4444444444

Simplifying
c2 = 0.4444444444

Take the square root of each side:
c = {-0.666666667, 0.666666667}