(3c+2)+4(1.3c-5)=c

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Solution for (3c+2)+4(1.3c-5)=c equation: 



(3c+2)+4(1.3c-5)=c

We move all terms to the left:

(3c+2)+4(1.3c-5)-(c)=0

We add all the numbers together, and all the variables

-1c+(3c+2)+4(1.3c-5)=0

We multiply parentheses

-1c+(3c+2)+4c-20=0

We get rid of parentheses

-1c+3c+4c+2-20=0

We add all the numbers together, and all the variables

6c-18=0

We move all terms containing c to the left, all other terms to the right

6c=18

c=18/6

c=3

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