(3c+27)-25=12

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Solution for (3c+27)-25=12 equation:



(3c+27)-25=12
We move all terms to the left:
(3c+27)-25-(12)=0
We add all the numbers together, and all the variables
(3c+27)-37=0
We get rid of parentheses
3c+27-37=0
We add all the numbers together, and all the variables
3c-10=0
We move all terms containing c to the left, all other terms to the right
3c=10
c=10/3
c=3+1/3

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