(3c+2c)(5+c)-(2c)(5)=

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Solution for (3c+2c)(5+c)-(2c)(5)= equation:


Simplifying
(3c + 2c)(5 + c) + -1(2c)(5) = 0

Combine like terms: 3c + 2c = 5c
(5c)(5 + c) + -1(2c)(5) = 0

Remove parenthesis around (5c)
5c(5 + c) + -1(2c)(5) = 0
(5 * 5c + c * 5c) + -1(2c)(5) = 0
(25c + 5c2) + -1(2c)(5) = 0

Remove parenthesis around (2c)
25c + 5c2 + -1 * 2c(5) = 0

Reorder the terms for easier multiplication:
25c + 5c2 + -1 * 2 * 5c = 0

Multiply -1 * 2
25c + 5c2 + -2 * 5c = 0

Multiply -2 * 5
25c + 5c2 + -10c = 0

Reorder the terms:
25c + -10c + 5c2 = 0

Combine like terms: 25c + -10c = 15c
15c + 5c2 = 0

Solving
15c + 5c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '5c'.
5c(3 + c) = 0

Ignore the factor 5.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(3 + c)' equal to zero and attempt to solve: Simplifying 3 + c = 0 Solving 3 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + c = 0 + -3 c = 0 + -3 Combine like terms: 0 + -3 = -3 c = -3 Simplifying c = -3

Solution

c = {0, -3}

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