(3c+4)(3c-4)=

Solution for (3c+4)(3c-4)= equation:

Simplifying
(3c + 4)(3c + -4) = 0

Reorder the terms:
(4 + 3c)(3c + -4) = 0

Reorder the terms:
(4 + 3c)(-4 + 3c) = 0

Multiply (4 + 3c) * (-4 + 3c)
(4(-4 + 3c) + 3c * (-4 + 3c)) = 0
((-4 * 4 + 3c * 4) + 3c * (-4 + 3c)) = 0
((-16 + 12c) + 3c * (-4 + 3c)) = 0
(-16 + 12c + (-4 * 3c + 3c * 3c)) = 0
(-16 + 12c + (-12c + 9c2)) = 0

Combine like terms: 12c + -12c = 0
(-16 + 0 + 9c2) = 0
(-16 + 9c2) = 0

Solving
-16 + 9c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 9c2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 9c2 = 0 + 16
9c2 = 0 + 16

Combine like terms: 0 + 16 = 16
9c2 = 16

Divide each side by '9'.
c2 = 1.777777778

Simplifying
c2 = 1.777777778

Take the square root of each side:
c = {-1.333333333, 1.333333333}