(3c+4)=2(c+6)+c

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Solution for (3c+4)=2(c+6)+c equation:



(3c+4)=2(c+6)+c
We move all terms to the left:
(3c+4)-(2(c+6)+c)=0
We get rid of parentheses
3c-(2(c+6)+c)+4=0
We calculate terms in parentheses: -(2(c+6)+c), so:
2(c+6)+c
We add all the numbers together, and all the variables
c+2(c+6)
We multiply parentheses
c+2c+12
We add all the numbers together, and all the variables
3c+12
Back to the equation:
-(3c+12)
We get rid of parentheses
3c-3c-12+4=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation

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