(3c+5)(3c-5)=

Solution for (3c+5)(3c-5)= equation:

Simplifying
(3c + 5)(3c + -5) = 0

Reorder the terms:
(5 + 3c)(3c + -5) = 0

Reorder the terms:
(5 + 3c)(-5 + 3c) = 0

Multiply (5 + 3c) * (-5 + 3c)
(5(-5 + 3c) + 3c * (-5 + 3c)) = 0
((-5 * 5 + 3c * 5) + 3c * (-5 + 3c)) = 0
((-25 + 15c) + 3c * (-5 + 3c)) = 0
(-25 + 15c + (-5 * 3c + 3c * 3c)) = 0
(-25 + 15c + (-15c + 9c2)) = 0

Combine like terms: 15c + -15c = 0
(-25 + 0 + 9c2) = 0
(-25 + 9c2) = 0

Solving
-25 + 9c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 9c2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 9c2 = 0 + 25
9c2 = 0 + 25

Combine like terms: 0 + 25 = 25
9c2 = 25

Divide each side by '9'.
c2 = 2.777777778

Simplifying
c2 = 2.777777778

Take the square root of each side:
c = {-1.666666667, 1.666666667}