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(3c+5)+55=180
We move all terms to the left:
(3c+5)+55-(180)=0
We add all the numbers together, and all the variables
(3c+5)-125=0
We get rid of parentheses
3c+5-125=0
We add all the numbers together, and all the variables
3c-120=0
We move all terms containing c to the left, all other terms to the right
3c=120
c=120/3
c=40
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