(3c-1)(3c+1)=

Solution for (3c-1)(3c+1)= equation:

Simplifying
(3c + -1)(3c + 1) = 0

Reorder the terms:
(-1 + 3c)(3c + 1) = 0

Reorder the terms:
(-1 + 3c)(1 + 3c) = 0

Multiply (-1 + 3c) * (1 + 3c)
(-1(1 + 3c) + 3c * (1 + 3c)) = 0
((1 * -1 + 3c * -1) + 3c * (1 + 3c)) = 0
((-1 + -3c) + 3c * (1 + 3c)) = 0
(-1 + -3c + (1 * 3c + 3c * 3c)) = 0
(-1 + -3c + (3c + 9c2)) = 0

Combine like terms: -3c + 3c = 0
(-1 + 0 + 9c2) = 0
(-1 + 9c2) = 0

Solving
-1 + 9c2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 9c2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 9c2 = 0 + 1
9c2 = 0 + 1

Combine like terms: 0 + 1 = 1
9c2 = 1

Divide each side by '9'.
c2 = 0.1111111111

Simplifying
c2 = 0.1111111111

Take the square root of each side:
c = {-0.333333333, 0.333333333}