(3c-1)(c+2)=0

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Solution for (3c-1)(c+2)=0 equation:


Simplifying
(3c + -1)(c + 2) = 0

Reorder the terms:
(-1 + 3c)(c + 2) = 0

Reorder the terms:
(-1 + 3c)(2 + c) = 0

Multiply (-1 + 3c) * (2 + c)
(-1(2 + c) + 3c * (2 + c)) = 0
((2 * -1 + c * -1) + 3c * (2 + c)) = 0
((-2 + -1c) + 3c * (2 + c)) = 0
(-2 + -1c + (2 * 3c + c * 3c)) = 0
(-2 + -1c + (6c + 3c2)) = 0

Combine like terms: -1c + 6c = 5c
(-2 + 5c + 3c2) = 0

Solving
-2 + 5c + 3c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-2 + -1c)(1 + -3c) = 0

Subproblem 1

Set the factor '(-2 + -1c)' equal to zero and attempt to solve: Simplifying -2 + -1c = 0 Solving -2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1c = 0 + 2 -1c = 0 + 2 Combine like terms: 0 + 2 = 2 -1c = 2 Divide each side by '-1'. c = -2 Simplifying c = -2

Subproblem 2

Set the factor '(1 + -3c)' equal to zero and attempt to solve: Simplifying 1 + -3c = 0 Solving 1 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -3c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -3c = 0 + -1 -3c = 0 + -1 Combine like terms: 0 + -1 = -1 -3c = -1 Divide each side by '-3'. c = 0.3333333333 Simplifying c = 0.3333333333

Solution

c = {-2, 0.3333333333}

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