(3c-2)=(7c+1)

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Solution for (3c-2)=(7c+1) equation: 



(3c-2)=(7c+1)

We move all terms to the left:

(3c-2)-((7c+1))=0

We get rid of parentheses

3c-((7c+1))-2=0



We calculate terms in parentheses: -((7c+1)), so:

(7c+1)

We get rid of parentheses

7c+1

Back to the equation:

-(7c+1)



We get rid of parentheses

3c-7c-1-2=0

We add all the numbers together, and all the variables

-4c-3=0

We move all terms containing c to the left, all other terms to the right

-4c=3

c=3/-4

c=-3/4

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