(3c-21)+(c+10)=c+50

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Solution for (3c-21)+(c+10)=c+50 equation: 



(3c-21)+(c+10)=c+50

We move all terms to the left:

(3c-21)+(c+10)-(c+50)=0

We get rid of parentheses

3c+c-c-21+10-50=0

We add all the numbers together, and all the variables

3c-61=0

We move all terms containing c to the left, all other terms to the right

3c=61

c=61/3

c=20+1/3

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