(3c-3)(2c+2c+5)=

Solution for (3c-3)(2c+2c+5)= equation:

Simplifying
(3c + -3)(2c + 2c + 5) = 0

Reorder the terms:
(-3 + 3c)(2c + 2c + 5) = 0

Reorder the terms:
(-3 + 3c)(5 + 2c + 2c) = 0

Combine like terms: 2c + 2c = 4c
(-3 + 3c)(5 + 4c) = 0

Multiply (-3 + 3c) * (5 + 4c)
(-3(5 + 4c) + 3c * (5 + 4c)) = 0
((5 * -3 + 4c * -3) + 3c * (5 + 4c)) = 0
((-15 + -12c) + 3c * (5 + 4c)) = 0
(-15 + -12c + (5 * 3c + 4c * 3c)) = 0
(-15 + -12c + (15c + 12c2)) = 0

Combine like terms: -12c + 15c = 3c
(-15 + 3c + 12c2) = 0

Solving
-15 + 3c + 12c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '3'.
3(-5 + c + 4c2) = 0

Factor a trinomial.
3((-5 + -4c)(1 + -1c)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(-5 + -4c)' equal to zero and attempt to solve:

Simplifying
-5 + -4c = 0

Solving
-5 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -4c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -4c = 0 + 5
-4c = 0 + 5

Combine like terms: 0 + 5 = 5
-4c = 5

Divide each side by '-4'.
c = -1.25

Simplifying
c = -1.25
Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Solution
c = {-1.25, 1}