(3c-4)(3c-4)=0

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Solution for (3c-4)(3c-4)=0 equation: 



(3c-4)(3c-4)=0

We multiply parentheses ..

(+9c^2-12c-12c+16)=0

We get rid of parentheses

9c^2-12c-12c+16=0

We add all the numbers together, and all the variables

9c^2-24c+16=0

a = 9; b = -24; c = +16;
Δ = b2-4ac
Δ = -242-4·9·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{24}{18}=1+1/3$

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