(3c-4/4)=4-(c-5/2)

Solution for (3c-4/4)=4-(c-5/2) equation:

(3c-4/4)=4-(c-5/2)

We move all terms to the left:

(3c-4/4)-(4-(c-5/2))=0

We add all the numbers together, and all the variables

(3c-1)-(4-(+c-5/2))=0

We get rid of parentheses

3c-(4-(+c-5/2))-1=0

We multiply all the terms by the denominator


3c*2))-(4-(+c-5-1*2))=0

We add all the numbers together, and all the variables

3c*2))-(4-(c-7))=0

We add all the numbers together, and all the variables

3c*2))-(4-(c=0

Wy multiply elements

6c^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{12}=0$