(3c-7/2c+1)/(2c+1/1-2c)

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Solution for (3c-7/2c+1)/(2c+1/1-2c) equation: 


D( c )

2*c-(2*c)+1/1 = 0

2*c-(2*c)+1/1 = 0

2*c-(2*c)+1/1 = 0

2*c-2*c+1 = 0

1 = 0

c belongs to the empty set

c in (-oo:+oo)

(3*c-((7/2)*c)+1)/(2*c-(2*c)+1/1) = 0

(3*c+(-7/2)*c+1)/(2*c-2*c+1) = 0

(1-1/2*c)/1 = 0

1-1/2*c = 0 // - 1

-1/2*c = -1 // : -1/2

c = -1/(-1/2)

c = 2

c = 2

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