(3c=2)+4(1.3c-5)=0

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Solution for (3c=2)+4(1.3c-5)=0 equation: 



(3c=2)+4(1.3c-5)=0

We move all terms to the left:

(3c-(2)+4(1.3c-5))=0



We calculate terms in parentheses: +(3c-2+4(1.3c-5)), so:

3c-2+4(1.3c-5)

determiningTheFunctionDomain
3c+4(1.3c-5)-2

We multiply parentheses

3c+4c-20-2

We add all the numbers together, and all the variables

7c-22

Back to the equation:

+(7c-22)



We get rid of parentheses

7c-22=0

We move all terms containing c to the left, all other terms to the right

7c=22

c=22/7

c=3+1/7

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