(3d-12)-(2d+3)=d-15

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Solution for (3d-12)-(2d+3)=d-15 equation: 



(3d-12)-(2d+3)=d-15

We move all terms to the left:

(3d-12)-(2d+3)-(d-15)=0

We get rid of parentheses

3d-2d-d-12-3+15=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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