(3d-2)(2d+5)=0

Solution for (3d-2)(2d+5)=0 equation:

(3d-2)(2d+5)=0

We multiply parentheses ..

(+6d^2+15d-4d-10)=0

We get rid of parentheses

6d^2+15d-4d-10=0

We add all the numbers together, and all the variables

6d^2+11d-10=0

a = 6; b = 11; c = -10;
Δ = b2-4ac
Δ = 112-4·6·(-10)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-19}{2*6}=\frac{-30}{12}
=-2+1/2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+19}{2*6}=\frac{8}{12}
=2/3
$