(3d-5)(3d-2)=0

Solution for (3d-5)(3d-2)=0 equation:

(3d-5)(3d-2)=0

We multiply parentheses ..

(+9d^2-6d-15d+10)=0

We get rid of parentheses

9d^2-6d-15d+10=0

We add all the numbers together, and all the variables

9d^2-21d+10=0

a = 9; b = -21; c = +10;
Δ = b2-4ac
Δ = -212-4·9·10
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9}{2*9}=\frac{12}{18}
=2/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9}{2*9}=\frac{30}{18}
=1+2/3
$