(3f+1)/4=(3+2f)/2

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Solution for (3f+1)/4=(3+2f)/2 equation: 



(3f+1)/4=(3+2f)/2

We move all terms to the left:

(3f+1)/4-((3+2f)/2)=0

We add all the numbers together, and all the variables

(3f+1)/4-((2f+3)/2)=0

We calculate fractions


3f/()+(-((2f+3)*4)/()=0



We calculate terms in parentheses: +(-((2f+3)*4)/(), so:

-((2f+3)*4)/(

We multiply all the terms by the denominator


-((2f+3)*4)



We calculate terms in parentheses: -((2f+3)*4), so:

(2f+3)*4

We multiply parentheses

8f+12

Back to the equation:

-(8f+12)



We get rid of parentheses

-8f-12

Back to the equation:

+(-8f-12)



We get rid of parentheses

3f/()-8f-12=0

We multiply all the terms by the denominator


3f-8f*()-12*()=0

We add all the numbers together, and all the variables

3f-8f*()=0

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