(3h/5)-17=(37/30)

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Solution for (3h/5)-17=(37/30) equation:



(3h/5)-17=(37/30)
We move all terms to the left:
(3h/5)-17-((37/30))=0
We add all the numbers together, and all the variables
(+3h/5)-17-((+37/30))=0
We get rid of parentheses
3h/5-17-((+37/30))=0
We calculate fractions
90h^2/()-17+()/()=0
We add all the numbers together, and all the variables
90h^2/()-16=0
We multiply all the terms by the denominator
90h^2-16*()=0
We add all the numbers together, and all the variables
90h^2=0
a = 90; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·90·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{180}=0$

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