(3i+4)(-3i+4)=

Solution for (3i+4)(-3i+4)= equation:

Simplifying
(3i + 4)(-3i + 4) = 0

Reorder the terms:
(4 + 3i)(-3i + 4) = 0

Reorder the terms:
(4 + 3i)(4 + -3i) = 0

Multiply (4 + 3i) * (4 + -3i)
(4(4 + -3i) + 3i * (4 + -3i)) = 0
((4 * 4 + -3i * 4) + 3i * (4 + -3i)) = 0
((16 + -12i) + 3i * (4 + -3i)) = 0
(16 + -12i + (4 * 3i + -3i * 3i)) = 0
(16 + -12i + (12i + -9i2)) = 0

Combine like terms: -12i + 12i = 0
(16 + 0 + -9i2) = 0
(16 + -9i2) = 0

Solving
16 + -9i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -9i2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -9i2 = 0 + -16
-9i2 = 0 + -16

Combine like terms: 0 + -16 = -16
-9i2 = -16

Divide each side by '-9'.
i2 = 1.777777778

Simplifying
i2 = 1.777777778

Take the square root of each side:
i = {-1.333333333, 1.333333333}