(3i-18)/6=2

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Solution for (3i-18)/6=2 equation: 



(3i-18)/6=2

We move all terms to the left:

(3i-18)/6-(2)=0

We multiply all the terms by the denominator


(3i-18)-2*6=0

We add all the numbers together, and all the variables

(3i-18)-12=0

We get rid of parentheses

3i-18-12=0

We add all the numbers together, and all the variables

3i-30=0

We move all terms containing i to the left, all other terms to the right

3i=30

i=30/3

i=10

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