(3j+11)+(8j-7)=j=

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Solution for (3j+11)+(8j-7)=j= equation: 



(3j+11)+(8j-7)=j=

We move all terms to the left:

(3j+11)+(8j-7)-(j)=0

We add all the numbers together, and all the variables

-1j+(3j+11)+(8j-7)=0

We get rid of parentheses

-1j+3j+8j+11-7=0

We add all the numbers together, and all the variables

10j+4=0

We move all terms containing j to the left, all other terms to the right

10j=-4

j=-4/10

j=-2/5

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