(3j+2)/4=(7j-2)/6

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Solution for (3j+2)/4=(7j-2)/6 equation: 



(3j+2)/4=(7j-2)/6

We move all terms to the left:

(3j+2)/4-((7j-2)/6)=0

We calculate fractions


3j/()+(-((7j-2)*4)/()=0



We calculate terms in parentheses: +(-((7j-2)*4)/(), so:

-((7j-2)*4)/(

We multiply all the terms by the denominator


-((7j-2)*4)



We calculate terms in parentheses: -((7j-2)*4), so:

(7j-2)*4

We multiply parentheses

28j-8

Back to the equation:

-(28j-8)



We get rid of parentheses

-28j+8

Back to the equation:

+(-28j+8)



We get rid of parentheses

3j/()-28j+8=0

We multiply all the terms by the denominator


3j-28j*()+8*()=0

We add all the numbers together, and all the variables

3j-28j*()=0

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