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(3k+1)=(8)
We move all terms to the left:
(3k+1)-((8))=0
determiningTheFunctionDomain (3k+1)-8=0
We get rid of parentheses
3k+1-8=0
We add all the numbers together, and all the variables
3k-7=0
We move all terms containing k to the left, all other terms to the right
3k=7
k=7/3
k=2+1/3
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