(3k+2)/k+(k-4)/k

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Solution for (3k+2)/k+(k-4)/k equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

(3*k+2)/k+(k-4)/k = 0

3*k+k-4+2 = 0

4*k-2 = 0

(4*k-2)/k = 0

(4*k-2)/k = 0 // * k

4*k-2 = 0

4*k-2 = 0 // + 2

4*k = 2 // : 4

k = 2/4

k = 1/2

k = 1/2

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