(3k+4)+(k+4)=72

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Solution for (3k+4)+(k+4)=72 equation:



(3k+4)+(k+4)=72
We move all terms to the left:
(3k+4)+(k+4)-(72)=0
We get rid of parentheses
3k+k+4+4-72=0
We add all the numbers together, and all the variables
4k-64=0
We move all terms containing k to the left, all other terms to the right
4k=64
k=64/4
k=16

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