(3k+7/4)-6=10

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Solution for (3k+7/4)-6=10 equation:



(3k+7/4)-6=10
We move all terms to the left:
(3k+7/4)-6-(10)=0
We add all the numbers together, and all the variables
(+3k+7/4)-6-10=0
We add all the numbers together, and all the variables
(+3k+7/4)-16=0
We get rid of parentheses
3k-16+7/4=0
We multiply all the terms by the denominator
3k*4+7-16*4=0
We add all the numbers together, and all the variables
3k*4-57=0
Wy multiply elements
12k-57=0
We move all terms containing k to the left, all other terms to the right
12k=57
k=57/12
k=4+3/4

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