(3k-4)(1-2k)=6

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Solution for (3k-4)(1-2k)=6 equation:



(3k-4)(1-2k)=6
We move all terms to the left:
(3k-4)(1-2k)-(6)=0
We add all the numbers together, and all the variables
(3k-4)(-2k+1)-6=0
We multiply parentheses ..
(-6k^2+3k+8k-4)-6=0
We get rid of parentheses
-6k^2+3k+8k-4-6=0
We add all the numbers together, and all the variables
-6k^2+11k-10=0
a = -6; b = 11; c = -10;
Δ = b2-4ac
Δ = 112-4·(-6)·(-10)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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