(3m)/4-(m/12)=(7/8)

Solution for (3m)/4-(m/12)=(7/8) equation:

(3m)/4-(m/12)=(7/8)

We move all terms to the left:

(3m)/4-(m/12)-((7/8))=0

We add all the numbers together, and all the variables

3m/4-(+m/12)-((+7/8))=0

We get rid of parentheses

3m/4-m/12-((+7/8))=0

We calculate fractions


(-256m^2)/()+2304m^2/()+()/()=0

We add all the numbers together, and all the variables

(-256m^2)/()+2304m^2/()+1=0

We multiply all the terms by the denominator


(-256m^2)+2304m^2+1*()=0

We add all the numbers together, and all the variables

2304m^2+(-256m^2)=0

We get rid of parentheses

2304m^2-256m^2=0

We add all the numbers together, and all the variables

2048m^2=0

a = 2048; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2048·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{4096}=0$