(3m+19)/6+15m=(7-m)/8

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Solution for (3m+19)/6+15m=(7-m)/8 equation: 



(3m+19)/6+15m=(7-m)/8

We move all terms to the left:

(3m+19)/6+15m-((7-m)/8)=0

We add all the numbers together, and all the variables

(3m+19)/6+15m-((-1m+7)/8)=0

We add all the numbers together, and all the variables

15m+(3m+19)/6-((-1m+7)/8)=0

We calculate fractions


15m+3m/()+(-((-1m+7)*6)/()=0



We calculate terms in parentheses: +(-((-1m+7)*6)/(), so:

-((-1m+7)*6)/(

We multiply all the terms by the denominator


-((-1m+7)*6)



We calculate terms in parentheses: -((-1m+7)*6), so:

(-1m+7)*6

We multiply parentheses

-6m+42

Back to the equation:

-(-6m+42)



We get rid of parentheses

6m-42

Back to the equation:

+(6m-42)



We get rid of parentheses

15m+3m/()+6m-42=0

We multiply all the terms by the denominator


15m*()+3m+6m*()-42*()=0

We add all the numbers together, and all the variables

3m+15m*()+6m*()=0

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