(3m+2)(m+4)=0

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Solution for (3m+2)(m+4)=0 equation:



(3m+2)(m+4)=0
We multiply parentheses ..
(+3m^2+12m+2m+8)=0
We get rid of parentheses
3m^2+12m+2m+8=0
We add all the numbers together, and all the variables
3m^2+14m+8=0
a = 3; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·3·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*3}=\frac{-24}{6} =-4 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*3}=\frac{-4}{6} =-2/3 $

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