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(3m+3)(4m+3)=0
We multiply parentheses ..
(+12m^2+9m+12m+9)=0
We get rid of parentheses
12m^2+9m+12m+9=0
We add all the numbers together, and all the variables
12m^2+21m+9=0
a = 12; b = 21; c = +9;
Δ = b2-4ac
Δ = 212-4·12·9
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-3}{2*12}=\frac{-24}{24} =-1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+3}{2*12}=\frac{-18}{24} =-3/4 $
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