(3m+5)/5=(4+m)/2

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Solution for (3m+5)/5=(4+m)/2 equation: 



(3m+5)/5=(4+m)/2

We move all terms to the left:

(3m+5)/5-((4+m)/2)=0

We add all the numbers together, and all the variables

(3m+5)/5-((m+4)/2)=0

We calculate fractions


3m/()+(-((m+4)*5)/()=0



We calculate terms in parentheses: +(-((m+4)*5)/(), so:

-((m+4)*5)/(

We multiply all the terms by the denominator


-((m+4)*5)



We calculate terms in parentheses: -((m+4)*5), so:

(m+4)*5

We multiply parentheses

5m+20

Back to the equation:

-(5m+20)



We get rid of parentheses

-5m-20

Back to the equation:

+(-5m-20)



We get rid of parentheses

3m/()-5m-20=0

We multiply all the terms by the denominator


3m-5m*()-20*()=0

We add all the numbers together, and all the variables

3m-5m*()=0

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