(3m-2)(9m+5)=0,

Solution for (3m-2)(9m+5)=0, equation:

(3m-2)(9m+5)=0.

We multiply parentheses ..

(+27m^2+15m-18m-10)=0

We get rid of parentheses

27m^2+15m-18m-10=0

We add all the numbers together, and all the variables

27m^2-3m-10=0

a = 27; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·27·(-10)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-33}{2*27}=\frac{-30}{54}
=-5/9
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+33}{2*27}=\frac{36}{54}
=2/3
$