(3n+1)(n+3)-n(3n+7)=3(n+1)

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Solution for (3n+1)(n+3)-n(3n+7)=3(n+1) equation: 



(3n+1)(n+3)-n(3n+7)=3(n+1)

We move all terms to the left:

(3n+1)(n+3)-n(3n+7)-(3(n+1))=0

We multiply parentheses

-3n^2+(3n+1)(n+3)-7n-(3(n+1))=0

We multiply parentheses ..

-3n^2+(+3n^2+9n+n+3)-7n-(3(n+1))=0



We calculate terms in parentheses: -(3(n+1)), so:

3(n+1)

We multiply parentheses

3n+3

Back to the equation:

-(3n+3)



We get rid of parentheses

-3n^2+3n^2+9n+n-7n-3n+3-3=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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