(3n+2)(n+1)=

Solution for (3n+2)(n+1)= equation:

Simplifying
(3n + 2)(n + 1) = 0

Reorder the terms:
(2 + 3n)(n + 1) = 0

Reorder the terms:
(2 + 3n)(1 + n) = 0

Multiply (2 + 3n) * (1 + n)
(2(1 + n) + 3n * (1 + n)) = 0
((1 * 2 + n * 2) + 3n * (1 + n)) = 0
((2 + 2n) + 3n * (1 + n)) = 0
(2 + 2n + (1 * 3n + n * 3n)) = 0
(2 + 2n + (3n + 3n2)) = 0

Combine like terms: 2n + 3n = 5n
(2 + 5n + 3n2) = 0

Solving
2 + 5n + 3n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(1 + n)(2 + 3n) = 0

Subproblem 1
Set the factor '(1 + n)' equal to zero and attempt to solve:

Simplifying
1 + n = 0

Solving
1 + n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + n = 0 + -1
n = 0 + -1

Combine like terms: 0 + -1 = -1
n = -1

Simplifying
n = -1
Subproblem 2
Set the factor '(2 + 3n)' equal to zero and attempt to solve:

Simplifying
2 + 3n = 0

Solving
2 + 3n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 3n = 0 + -2
3n = 0 + -2

Combine like terms: 0 + -2 = -2
3n = -2

Divide each side by '3'.
n = -0.6666666667

Simplifying
n = -0.6666666667
Solution
n = {-1, -0.6666666667}