(3n+2)/(7-4n)=2

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Solution for (3n+2)/(7-4n)=2 equation: 



(3n+2)/(7-4n)=2

We move all terms to the left:

(3n+2)/(7-4n)-(2)=0



Domain of the equation: (7-4n)!=0

We move all terms containing n to the left, all other terms to the right

-4n!=-7

n!=-7/-4

n!=1+3/4

n∈R



We add all the numbers together, and all the variables

(3n+2)/(-4n+7)-2=0

We multiply all the terms by the denominator


(3n+2)-2*(-4n+7)=0

We multiply parentheses

(3n+2)+8n-14=0

We get rid of parentheses

3n+8n+2-14=0

We add all the numbers together, and all the variables

11n-12=0

We move all terms containing n to the left, all other terms to the right

11n=12

n=12/11

n=1+1/11

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