(3n+2)=(2n-5)

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Solution for (3n+2)=(2n-5) equation: 



(3n+2)=(2n-5)

We move all terms to the left:

(3n+2)-((2n-5))=0

We get rid of parentheses

3n-((2n-5))+2=0



We calculate terms in parentheses: -((2n-5)), so:

(2n-5)

We get rid of parentheses

2n-5

Back to the equation:

-(2n-5)



We get rid of parentheses

3n-2n+5+2=0

We add all the numbers together, and all the variables

n+7=0

We move all terms containing n to the left, all other terms to the right

n=-7

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